Калькулятор Сочетаний

Калькулятор Сочетаний вычисляет C(n, k) — количество различных подмножеств размера k, извлечённых из набора из n элементов. Формула: C(n, k) = n! / (k! × (n−k)!), часто записывается как 'n выбрать k' или биномиальный коэффициент.

Try a worked example

Combinations vs permutations. Combinations count selections where order DOESN'T matter (a 5-card hand is the same regardless of how it was dealt). Permutations count arrangements where order MATTERS (gold-silver-bronze finish). C(n, k) is always less than P(n, k) by a factor of k!.

Как использовать

  1. 1

    Введите n — общее количество различных доступных элементов.

  2. 2

    Введите k — количество элементов, которые вы выбираете (k должно быть ≤ n).

  3. 3

    C(n, k) появляется мгновенно вместе с формулой.

  4. 4

    Для очень больших результатов (>30 цифр) калькулятор переключается на научную нотацию.

  5. 5

    Нажмите на пример, чтобы загрузить классические задачи.

Часто задаваемые вопросы

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What is a combination?

A combination is a selection of items from a larger set where the order of selection doesn't matter. If you're picking 3 books to take on vacation from a shelf of 10, the trio {Crime and Punishment, Dune, The Hobbit} is the same combination as {Dune, The Hobbit, Crime and Punishment} — same three books, you don't care which order you grabbed them in.

The number of distinct combinations of k items chosen from n items is given by the formula:

C(n, k) = n! / (k! × (n − k)!)

Pronounced "n choose k" and sometimes written as a vertical pair (n on top, k on bottom) inside parentheses. The same number is also called the binomial coefficient — it's the coefficient of xᵏ when you expand (1 + x)ⁿ. The numbers in Pascal's triangle are all binomial coefficients.

How to use the combination calculator

  1. Enter n — the total number of items you can choose from.
  2. Enter k — the size of the subset you're choosing. k must be between 0 and n inclusive.
  3. The result C(n, k) appears instantly with the formula displayed and a thousands-separator-formatted number.
  4. For very large outputs (more than 30 digits), the calculator switches to scientific notation.
  5. Tap a worked example to load classic combination problems — poker hands, lottery odds, committee selections.

Combinations vs permutations — the deciding question

Always ask: does the order matter?

  • YES, order matters → permutations. Gold-Silver-Bronze ≠ Bronze-Silver-Gold. Use P(n, k).
  • NO, order doesn't matter → combinations. {A, B, C} = {C, B, A}. Use C(n, k).

The relationship: C(n, k) = P(n, k) / k!. Combinations are always smaller than permutations by a factor of k! — because each combination corresponds to k! different orderings, all of which collapse into the same combination. C(5, 3) = 10; P(5, 3) = 60 = 10 × 3! = 10 × 6.

Worked examples

Example 1 — Pick 3 books from 5

You have 5 books and want to pick 3 to take on a trip. How many different sets of 3 are possible?

C(5, 3) = 5! / (3! × 2!) = 120 / 12 = 10. Just 10 distinct trios — the order you grab them doesn't matter, only which 3 you end up with.

Example 2 — 5-card poker hands

From a standard 52-card deck, how many different 5-card hands are possible?

C(52, 5) = 2,598,960. About 2.6 million distinct hands. The order you're dealt the cards doesn't matter (a royal flush is a royal flush regardless of which order the cards came out). All of poker probability builds on this number.

Example 3 — UK Lotto: 6 of 49

The UK Lotto requires you to pick 6 numbers from 1-49. How many tickets are needed to cover every combination?

C(49, 6) = 13,983,816. Nearly 14 million combinations. At £2 per ticket, buying every combination would cost about £28 million — far more than the typical jackpot. The "you can guarantee a win by buying every ticket" strategy only works on much smaller lotteries.

Example 4 — Committee selection

You need to pick a 3-person committee from 10 candidates. How many different committees can you form?

C(10, 3) = 120. The order doesn't matter — Alice, Bob, and Carol form the same committee whether you list them in any order. (If you were assigning specific roles like Chair, Vice-Chair, Treasurer, you'd want permutations: P(10, 3) = 720.)

Example 5 — Powerball white balls

The US Powerball draws 5 white balls from 1-69, plus a separate red ball from 1-26. The white-ball portion alone:

C(69, 5) = 11,238,513. About 11.2 million white-ball combinations. Multiply by 26 red-ball options = 292,201,338 total tickets. The "1 in 292 million" odds you hear quoted for Powerball jackpot wins comes directly from this multiplication.

The symmetry property: C(n, k) = C(n, n−k)

An elegant fact: choosing k items to KEEP from n is the same as choosing (n−k) items to DISCARD. Every selection has a complementary selection of the same kind, so the count must be the same.

  • C(10, 3) = C(10, 7) = 120
  • C(52, 5) = C(52, 47) = 2,598,960
  • C(100, 1) = C(100, 99) = 100

The calculator exploits this internally — when computing C(100, 99), it actually computes C(100, 1) = 100, which is far faster (1 multiplication vs 99). This is why the tool can handle n up to 1000 without slowing down.

Pascal's triangle — combinations on display

Pascal's triangle is a visual layout of every C(n, k):

            1                  ← C(0, 0)
          1   1                ← C(1, 0), C(1, 1)
        1   2   1              ← C(2, 0), C(2, 1), C(2, 2)
      1   3   3   1            ← C(3, k)
    1   4   6   4   1          ← C(4, k)
  1   5   10  10  5   1        ← C(5, k)
1   6  15  20  15   6   1      ← C(6, k)

Each row n contains C(n, 0), C(n, 1), ..., C(n, n). Each entry equals the sum of the two entries directly above it (the "Pascal's rule": C(n+1, k+1) = C(n, k) + C(n, k+1)). The triangle is symmetric (C(n, k) = C(n, n−k)) and the row sums are powers of 2 (the sum of row n equals 2ⁿ).

Combinations with repetition

The basic C(n, k) formula assumes WITHOUT repetition — each item appears in your subset at most once. If items can repeat (like choosing 3 ice cream scoops from 5 flavors where you can pick chocolate twice), the formula changes:

C with repetition = C(n + k − 1, k)

Choosing 3 scoops from 5 flavors (repeats allowed): C(5 + 3 − 1, 3) = C(7, 3) = 35.

This calculator uses the no-repetition formula. For with-repetition problems, compute C(n + k − 1, k) using the same calculator with adjusted n.

Where combinations show up

Lottery odds

Every "pick X numbers from Y" lottery is a combination problem. Mega Millions: pick 5 from 70 (C(70, 5) = 12.1M) plus 1 from 25 = 302.5M total combinations. The math is what determines the headline jackpot odds.

Poker probability

Royal flush: 4 ways out of 2,598,960 hands = 1 in 649,740. Straight flush: 36 / 2.6M = 1 in 72,193. Every hand probability is "favorable combinations / total combinations."

Sports brackets

NCAA March Madness Round of 64 → 32: choosing which 32 teams advance from any 64 = C(64, 32) ≈ 1.83 × 10¹⁸ possibilities (but only 2³² = 4.3B if order in the bracket doesn't matter). Every bracket-pool participant is sampling one of these.

Combinatorial chemistry

Drug screening: from a library of 1000 candidate molecules, how many 5-molecule cocktails could you test? C(1000, 5) = 8.25 × 10¹². This is why brute-force combinatorial drug discovery requires careful pruning — the search space is enormous.

Committee and team formation

Workplace teams, jury selection, study groups — anywhere you select a subset of people for a role-undifferentiated task is a combination problem.

Statistics and probability

Binomial distributions, hypergeometric distributions, sampling without replacement — all use combinations as their counting building block.

Special cases worth knowing

  • C(n, 0) = 1 — there's exactly one way to choose nothing (the empty set).
  • C(n, n) = 1 — exactly one way to choose all items.
  • C(n, 1) = n — choose just one of n items, n ways.
  • C(n, n−1) = n — by symmetry with C(n, 1).
  • C(2k, k) = the central binomial coefficient — peak of row 2k in Pascal's triangle, often the largest value in the row.

Common mistakes

  • Confusing C with P. The single most common error in combinatorics. Always ask "does the order matter?" If yes, use permutations.
  • Forgetting the (n−k)! in the denominator. The full formula has n! / (k! × (n−k)!) — three factorials, not two. Easy to drop one when scribbling on paper.
  • Thinking C(n, k) and P(n, k) are interchangeable for "small" k. They're never the same (except trivially when k = 0 or k = 1). Always check what the question is asking.
  • Using the no-repetition formula when items can repeat. A vending machine with 5 buttons where you press 3 (repeats allowed) gives 5³ = 125 outcomes (ordered with repetition), or C(7, 3) = 35 (unordered with repetition), NOT C(5, 3) = 10.
  • Confusing 'combination lock' with combinatorial combinations. A combination lock requires the right SEQUENCE of numbers — that's a permutation, not a combination. A 3-digit lock with 40 positions has 40³ = 64,000 sequences (with repetition), not C(40, 3).

What the calculator gives you, summarized

  • Exact C(n, k) — computed via BigInt for precision up to n = 1000.
  • Thousands-separator formatting — for results small enough to display normally, with commas (US-style) for readability.
  • Scientific approximation — for results with more than ~30 digits, displayed as m × 10ᵉ.
  • Formula display — n! / (k! × (n−k)!) shown with your numbers plugged in.
  • Worked examples — poker hands, UK Lotto, Powerball white balls, and committee picks all loadable with one tap.
  • Combinations-vs-permutations callout — the most-confused topic in combinatorics, called out inline.

Two inputs (n and k), one BigInt-precise output. The math is just division of factorials, but the answers explain everything from poker odds to bracket pools to lottery probabilities.